The Best Oracle 1z0-071 Study Guides and Dumps of 2024
Top Oracle 1z0-071 Exam Audio Study Guide! Practice Questions Edition
NEW QUESTION # 83
Examine the structure proposed for the TRANSACTIONS table:
Which two statements are true regarding the creation and storage of data in the above table structure? (Choose two.)
- A. The TRANS_VALIDITY column would have a maximum size of one character.
- B. The TRANS_VALIDITY column would give an error.
- C. The CUST_STATUS column would give an error.
- D. The CUST_STATUS column would store exactly one character.
- E. The CUST_CREDIT_LIMIT column would be able to store decimal values.
- F. The TRANS_DATE column would be able to store day, month, century, year, hour, minutes, seconds, and fractions of seconds.
Answer: B,D
NEW QUESTION # 84
Examine the structure proposed for the TRANSACTIONStable:
Which two statements are true regarding the storage of data in the above table structure? (Choose two.)
- A. The CUST_CREDIT_VALUEcolumn would allow storage of positive and negative integers.
- B. The CUST_STATUScolumn would allow storage of data up to the maximum VARCHAR2size of 4,000 characters.
- C. The TRANS_DATEcolumn would allow storage of dates only in the dd-mon-yyyy format.
- D. The TRANS_VALIDITYcolumn would allow storage of a time interval in days, hours, minutes, and seconds.
Answer: A,D
NEW QUESTION # 85
View the Exhibit and examine the structure of the SALES and PRODUCTS tables. (Choose two.) In the SALES table, PROD_ID is the foreign key referencing PROD_ID in the PRODUCTS table. You must list each product ID and the number of times it has been sold.
Examine this query which is missing a JOIN operator:
SQL > SELECT p.prod_id, count(s.prod_id)
FROM products p ______________ sales s
ON p.prod_id = s.prod_id
GROUP BY p.prod_id;
Which two JOIN operations can be used to obtain the required output?
- A. RIGHT OUTER JOIN
- B. FULL OUTER JOIN
- C. LEFT OUETR JOIN
- D. JOIN
Answer: B,C
NEW QUESTION # 86
Examine the structure of the PROGRAMS table:
Which two SQL statements would execute successfully?
- A. SELECT NVL (MONTHS_BETWEEN (start_date, end_date), 'Ongoing') FROM
programs; - B. SELECT TO_DATE (NVL (SYSDATE-END_DATE, SYSDATE)) FROM programs;
- C. SELECT NVL (ADD_MONTHS (END_DATE,1) SYSDATE) FROM programs;
- D. SELECT NVL (TO_CHAR (MONTHS_BETWEEN (start-date, end_date)), 'Ongoing') FROM programs
Answer: C,D
NEW QUESTION # 87
Examine this data in the EMPLOYEES table:
Which statement will execute successfully?
Which statement will execute successfully?
- A. SELECT dept_id( INSTR(last_name, 'A'), SUM (salary) FROM employees GROUP BY dept_id;
- B. SELECT dept_id, LENGTH (last: name) , SUM(salary) FROM employees GROUP BV dept_id;
- C. SELECT dept_id, MAX (last_name) . SUM(salary) FROM employees GROUP BY dept_id;
- D. SELECT dept_id, STDDEV(last_name), SUM( salary) FROM employees GROUP BV dept_id;
Answer: C
NEW QUESTION # 88
In which three situations does a transaction complete? (Choose three.)
- A. when a TRUNCATE statement is executed after the pending transaction
- B. when a ROLLBACK command is executed
- C. when a PL/SQL anonymous block is executed
- D. when a DELETE statement is executed
- E. when a data definition language (DDL) statement is executed
Answer: A,B,E
Explanation:
https://docs.oracle.com/cd/B19306_01/server.102/b14220/transact.htm
NEW QUESTION # 89
Which three statements are true about the Oracle join and ANSI join syntax? (Choose three.)
- A. The Oracle join syntax supports natural joins.
- B. The Oracle join syntax performs less well than the SQL:1999 compliant ANSI join syntax.
- C. The Oracle join syntax only supports right outer joins.
- D. The SQL:1999 compliant ANSI join syntax supports natural joins.
- E. The Oracle join syntax performs better than the SQL:1999 compliant ANSI join syntax.
- F. The SQL:1999 compliant ANSI join syntax supports creation of a Cartesian product of two tables.
- G. The Oracle join syntax supports creation of a Cartesian product of two tables.
Answer: A,D,F
Explanation:
Explanation/Reference: http://www.dba-oracle.com/oracle_tips_iso99_joins.htm
NEW QUESTION # 90
You are designing the structure of a table in which two columns have the specifications:
COMPONENT_ID- must be able to contain a maximum of 12 alphanumeric characters and uniquely identify the row
EXECUTION_DATETIME- contains Century, Year, Month, Day, Hour, Minute, Second to the maximum precision and is used for calculations and comparisons between components.
Which two options define the data types that satisfy these requirements most efficiently?
- A. The COMPONENT_IDcolumn must be of CHAR data type.
- B. The COMPONENT_IDmust be of VARCHAR2 data type.
- C. The EXECUTION_DATETIME must be of DATE data type.
- D. The EXECUTION_DATETIME must be of INTERVAL DAY TO SECOND data type.
- E. The COMPONENT_IDmust be of ROWID data type.
- F. The EXECUTION_DATETIME must be of TIMESTAMP data type.
Answer: A,C
NEW QUESTION # 91
View the Exhibit and examine the structure of the PRODUCTS table. (Choose the best answer.)
You must display the category with the maximum number of items.
You issue this query:
SQL > SELECT COUNT(*), prod_category_id
FROM products
GROUP BY prod_category_id
HAVING COUNT(*) = (SELECT MAX(COUNT(*)) FROM porducts);
What is the result?
- A. It generate an error because the subquery does not have a GROUP BY clause.
- B. It executes successfully and gives the correct output.
- C. It executes successfully but does not give the correct output.
- D. It generates an error because = is not valid and should be replaced by the IN operator.
Answer: A
NEW QUESTION # 92
Examine the description of the EMPLOYEES table:
NLS_DATE FORMAT is DD-MON-RR.
Which two queries will execute successfully?
- A. SELECT AVG(MAX(salary)) FROM employees GROUP BY salary;
- B. SELECT dept id, MAX (SUM(salary)) FROM employees GROUP BY dept_id;
- C. SELECT dept_ id, AVG(MAX(salary)) FROM employees GROUP BY dept_id, salary;
- D. SELECT dept_ id, AVG (MAX(salary)) FROM employees GROUP By dept_id HAVING hire_date> ' O1-JAN-19';
- E. SELECT dept_ iD, sum(salary) FROM employees WHERE hire_date > '01-JAN-9' GROUP BY dept_id;
Answer: A,E
NEW QUESTION # 93
Evaluate the following SQL statement:
SELECT product_name || 'it's not available for order'
FROM product_information
WHERE product_status = 'obsolete';
You received the following error while executing the above query:
ERROR:
ORA-01756: quoted string not properly terminated
What would you do to execute the query successfully?
- A. Enclose the character literal string in the SELECT clause within the double quotation marks.
- B. Use Quote (q) operator and delimiter to allow the use of single quotation mark in the literal character string.
- C. Do not enclose the character literal string in the SELECT clause within the single quotation marks.
- D. Use escape character to negate the single quotation mark inside the literal character string in the SELECT clause.
Answer: B
NEW QUESTION # 94
You want to return the current date and time from the user session, with a data type of TIMESTAMP WITH TIME ZONE.
Which function will do this?
- A. LOCALTIMESTAMP
- B. SYSDATE
- C. CURRENT_ TIMESTAMP
- D. CURRENT DATE
Answer: C
NEW QUESTION # 95
Examine these statements executed in a single Oracle session:
CREATE TABLE product (pcode NUMBER(2),pname VARCHAR2(20));
INSERT INTO product VALUES(1,'pen');
INSERT INTO product VALUES (2,'pencil');
INSERT INTO product VALUES(3,'fountain pen');
SAVEPOINT a;
UPDATE product SET pcode=10 WHERE pcode =1;
COMMIT;
DELETE FROM product WHERE pcode =2;
SAVEPOINT b;
UPDATE product SET pcode=30 WHERE pcode =3;
SAVEPOINT c;
DELETE FROM product WHERE pcode =10;
ROLLBACK TO SAVEPOINT b;
COMMIT;
Which three statements are true?
- A. The code for fountain pen is 3
- B. The code for pen is 10.
- C. There is no row containing pencil.
- D. There is no row containing pen
- E. There is no row containing fountain pen.
- F. The code for pen is 1.
Answer: A,B,C
NEW QUESTION # 96
Examine the description of the EMPLOYEES table:
Which statement increases each employee's SALARY by the minimum SALARY for their DEPARTM
ENT_ID?
- A. UPDATE employees e1
SET salary = salary+(SELECT MIN (salary)
FROM employees e2) ; - B. UPDATE employees e1
SET salary=
(SELECT e1.salary + MIN(e2.salary)
FROM employees e2
WHERE e1. department_ id = e2.department_id); - C. UPDATE employees e1
SET salary = salary +
(SELECT MIN(e1. salary)
FROM employees e2
WHERE e1.department_id = e2 .department_id); - D. UPDATE employees e1
SET salary =(SELECT e2. salary + MIN(e2.salary)
FROM employees e2
WHERE e1.department_ id = e2. department_id GROUP BY e2. department_id) ;
Answer: B
NEW QUESTION # 97
Examine these SQL statements that are executed in the given order:
What will be the status of the foreign key EMP_MGR_FK?
- A. It will remain disabled and can be re-enabled manually.
- B. It will be enabled and deferred.
- C. It will remain disabled and can be enabled only by dropping the foreign key constraint and re-creating it.
- D. It will be enabled and immediate.
Answer: A
NEW QUESTION # 98
Which statement is true regarding external tables?
- A. The data and metadata for an external table are stored outside the database.
- B. The CREATE TABLE AS SELECT statement can be used to upload data into a normal table in the database from an external table.
- C. ORACLE_LOADER and ORACLE_DATAPUMP have exactly the same functionality when used with an external table.
- D. The default REJECT LIMIT for external tables is UNLIMITED.
Answer: B
Explanation:
https://docs.oracle.com/cd/B28359_01/server.111/b28310/tables013.htm
NEW QUESTION # 99
Examine this partial command:
Which two clauses are required for this command to execute successfully? (Choose two.)
- A. the DEFAULT DIRECTORYclause
- B. the LOCATIONclause
- C. the REJECT LIMITclause
- D. the ACCESS PARAMETERSclause
- E. the access driver TYPEclause
Answer: A,B
NEW QUESTION # 100
Examine the description of the ORDERS table:
Which three statements execute successfully?
- A. (SELECT * FROM ORDERS
- B. SELECT ORDER_ID ORDER_DATE FROM ORDERS
UION ALL
SELECT INVOICE_ID, INVOICE_DATE FROM INVOICE ORDER BY ORDER_ID; - C. SELECT ORDER_ID INVOICE_ID ORDER-DATE FROM ORDERS
MINUS
SELECT INVOICE_ID INVOICE_DATA FROM INVOICE ORDER BY INVOICE_ID; - D. SELECT * FROM ORDERS ORDER BY ORDER_ID
UNION
SELECT * FROM INVOICES; - E. SELECT * FROM ORDERS ORDER BY ORDER_ID
INTERSECT
SELECT * FROM INVOICE ORDER BY INVOICE_ID;
Answer: B,C
NEW QUESTION # 101
Examine the structure of the PROMOTIONS table: (Choose the best answer.)
Management requires a report of unique promotion costs in each promotion category.
Which query would satisfy this requirement?
- A. SELECT DISTINCT promo_cost, DISTINCT promo_category FROM promotions;
- B. SELECT DISTINCT promo_cost, promo_category FROM promotions
- C. SELECT DISTINCT promo_category, promo_cost FROM promotions ORDER BY 1
- D. SELECT promo_category, DISTINCT promo_cost FROM promotions
Answer: C
NEW QUESTION # 102
Which statement is true regarding the INTERSECT operator?
- A. Reversing the order of the intersected tables alters the result.
- B. The number of columns and data types must be identical for all SELECT statements in the query.
INTERSECT Returns only the rows that occur in both queries' result sets, sorting them and removing duplicates.
The columns in the queries that make up a compound query can have different names, but the output result set will use the names of the columns in the first query. - C. The names of columns in all SELECT statements must be identical.
- D. It ignores NULLs.
Answer: B
NEW QUESTION # 103
Examine the description of the TRANSACTIONS table:
Which two SQL statements execute successfully?
- A. SELECT customer_id CUSTID, transaction_date TRANS_DATE, amount +100 DUES FROM transactions;
- B. SELECT customer_id AS CUSTOMER-ID, transaction_date AS TRANS_DATE, amount + 100
"DUES AMOUNT" FROM transactions; - C. SELECT customer_id AS 'CUSTOMER-ID', transaction_date AS DATE, amount + 100 'DUES' FROM transactions;
- D. SELECT customer_id AS "CUSTOMER-ID", transaction_date AS DATE, amount + 100 "DUES" FROM transactions;
- E. SELECT customer_id AS "CUSTOMER-ID", transaction_date AS "DATE", amount + 100 DUES FROM transactions;
Answer: A,E
NEW QUESTION # 104
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